PRANJALI PRBHA ( రోజువారి పద్య కథలు ) MALLAPRAGADA : *1.Mallapragada's Mathematics (Numbers-1)

Om Sri Ram Om Sri Ram Om Sri Ram

PREFACE

THE MATHEMATICS HAS BEEN PUBLISHED IN MY BLOG TO HELP STUDENTS TO TEST THEIR KNOWLEDGE. AND ALSO USEFUL FOR D.S.E.R.T, N.C.E.R.T., B.S.R.B. S.S.C., U.P.S.C., K.P.SC, OTHER COMPETITIVE EXAMINATIONS.AND QUIZ PROGRAM MES.

SUGGESTIONS AND CRITICISMS ARE MOST WELCOME FOR FURTHER IMPROVEMENT.

By.

Mallapragada ramakrishna, B.Sc.
Asst. Treasury Officer

Telugu writer and Mathematics Master .

https://vocaroo.com/i/s0vvg2z1VBXR

OBJECTIVE TYPE QUESTIONS for Competitions (Paper-1) ( NUMBERS)

1. 8888+888+88+8 =

2. 10000-5000-3000 =

3. ?- 10000 = 3000 =

4. ? + 123456 =654321 =

5. 10000-5000+5000-10000 =

6. 7014+6134+5978 = 7. 7589 _ ? = 3434 =

8. 3² + 4² + 5²^{+ 6^{2 =}}

9. 5²¹ + 5²² + 5²³ + 5²⁴ =

0. 4³¹ + 4³² + 4³³ + 4³⁴ =

1. Simplify : 57934 x 9999 =

12. Simplify: 12345 x 999 =

13. Simplify : 839478 x625 =

14. Simplify: 505 x 505 =

15. Simplify: 1605 x 1605 =

16. Simplify:495 x495 =

17. Simplify: 1595 x 1595 =

18. Evaluate: 213 x 213 + 113 x 113 =

19. Evaluate: 313x313 + 287 x287 =^,

20. Evaluate: 313x313 - 287 x287 =

21. 10000+1000+100+10 =

22. 123456789 x 72 =

23. 2014 x 1986 =

24. 200 x200 +100 x 100 + 2 x 200 x 100 =

25. 200 x 200 + 100 x 100 – 2 x 200 x 100 =

26. (475 +425)² – 4 x 475 x 425 =

27. 3000 + 2000 – a100 = 4000

28. Find the decimal value i.e. 1/2 = ?

29. Express 7/16,2/3 and 10/7 in decimal form ?

30. Express 3.28 in the form of P/Q

31. Express 1.62 in the p/q32. Show that 67920574 is divisible 4 =

32. Show that 67920562 is divisible 4

33. Show that 67920574 is divisible 11 =

34 Show that 4832718 is divisible 11 =

35. Show that 4832715 is divisible 2 =

36. Show that 4832715 is divisible 3 =

37. Show that 4832715 is divisible 5 =

38. Show that 4832715 is divisible 6 =

39. Show that 35256 is divisible 6 =

40. show that 35257 is divisible 8 =

41. how that 35360 is divisible 8 =

42. is 52563744 divisible by 24 =

43. what least valuemust be assigned to (*) so that the

number 197*5462 is divisible by 9 ?

^{Om Sri Ram Om Sri Ram Om Sri Ram}

SALVED ABOVE (PAPER -1)

OBJECTIVE TYYPE QUESTINS (Paper -1) ( NUMBERS)

1. 8888+888+88+8 = ? 9872

2. 10000-5000-3000 = ?
10000-(5000+3000)=2000

3. ?- 10000 = 3000 = ? let x-10000 = 3000 x = 3000 + 10000=13000

4. ? + 123456 =654321 = ? let x+123456=654321 : x= 654321 + 123456

= 777777

5. 10000-5000+5000-10000 = ? 0

6. 7014+6134+5978 = 19126

7. 7589 _ ? = 3434 = ? 7589 - X = 3434 , -X = 3434-7589= -4155

X=4155

8. 3² + 4² + 5² + 6² = ? 9 +16+25+36 = 86

9. 5²¹ + 5²² + 5²³ + 5²⁴ = ? 5²⁰ (1+5+5²+5³) = 5²⁰X (1+5+25+125) =

5²⁰ X 156

10. 4³¹ + 4³² + 4³³ + 4³⁴ = 4³⁰ (1+4+4²+4³ = 4³⁰X 340 (WHICH IS

CLEARLY DEVISIBLY BY 10)

11. Simplify : 57934 x 9999 =
57934 (1000-1) , 57934000 – 57934 =59876066

12. Simplify: 12345 x 999 =
12345(1000 – 1) , 12345000 – 12345 =12332655

13. Simplify : 839478 x625
= 839478 x 5⁴ = 8394780000 / 16 = 524673750

14. Simplify: 505 x 505 =
(505)², = (500+5)² ,= 500² + 5² + 2x500x5

=2500+25+1000= 3525

15. Simplify: 1605 x 1605 =
(1605)² , =(1600 + 5 )², =(1600)² + 5² +

2x1600x5

=2560000+25+16000=2576025

16. Simplify:495 x495 =
(500)², = (500-5)² ,= 500² + 5² - 2x500x5

=2500+25-1000=

17. Simplify: 1595 x 1595 =
(1595)² , =(1600 - 5 )², =(1600)²+ 5² - 2x1600x5

=2560000+25-16000=2400025

18 Evaluate: 213 x 213 + 113 x 113 =
(213)² + (113)²= ½ {(a+b)² + (a-b)²}

½ (213 +113)² + (213-113)² = ½{(326)²+(100)²)

=(106276+10000)/2 = 1630000

19 Evaluate: 313x313 + 287 x287 =
(313)² + (287)²= ½ {(a+b)² + (a-b)²}

½ (313 +287)² + (313-287)² = ½{600)² +(26)²

=1/2 (360000 +676) =180338

20. Evaluate: 313x313 - 287 x287 =
(313)²– (287)²= (313+287) x

(313-287)=600x26=15600

21. 10000+1000+100+10 =11110 --

22. 123456789 x 72                =
        123456789(100-28) = 12345678900 – (123456789 x 28)

12345678900 –(123456789 x (30-2),

        12345678900-370370370 + 24691358 =
             888888888

23 2014 x 1986 = (2000+14) x (2000-14),
(2000)² – (14)² = 4000000-196

=3999804

24 200 x200 +100 x 100 + 2 x 200 x 100 =
200 + 100)² = (300)² = 90000

25 200 x 200 + 100 x 100 – 2 x 200 x 100 =
(200 - 100)² = (100)² =10000

26 (475 +425)² – 4 x 475 x 425 =
(a-b)² = (a+b)² -4ab

(475 – 425 )² = (50)² =2500

27 3000 + 2000 – a100 = 4000
-a100 = 4000 –(3000+2000), -a100 = -1000 .. a = 10

28. Find the decimal value i.e. 1/2 = ?
      Ans. 0.5

29. Express 7/16,2/3 and 10/7 in decimal form ?
   Ans. 7/16= 0.4375, 10/7 = 1.428571, 2/3=0.666

30. Express 3.28 in the form of P/Q
       328/100 = 2(164)/2(50) = 82/25 = (NUMERATOR AND
        DENOMINATOR ARE CO-PRIMES)

31. Express 1.62 in the p/q

       let x = 1.6262.....................(1)
   multipling both sides of equation (1) b 100 weget
   100 x = 162.62...................(2)
   Submiting (2) from (1) we get
   100 x = 162.62..
x =    1.62..
   ----------------
99x = 161
-------------------
x = 161/99

      There fore 1.6262 = 161/99

32. Show that 67920574 is divisible 4 =

The Last two digits number is 74, which is not devisible by 4

33.Show that 67920562 is divisible 4

The Last two digits number is 72, which is devisible by 4

34 Show that 67920574 is divisible 11 =

{(Sum of digits at add place( – ( sum of digits at even places)}(4+5+2+7) – (7+0+9+6) = (18 – 22) is not divisible by 11

35 S how that 4832718 is divisible 11 =

{(Sum of digits at add place( – ( sum of digits at even

places)}(8+7+3+4) – (1+2+8) = (22 – 11) is divisible

by 11

36.   Show that 4832718 is divisible 2 =

If units digits is any of 0,2,4,6,8 is divisible by two

37.     Show that 4832715 is divisible 3 =

     A number is divisible by 3 , if the sum of the digits is

     divisibe by 3

    (4+8+3+2+7+1+6)=30 is not divisible by 3

38.     Show that 4832715 is divisible 5 =

        If units digits is any of 0,5 is divisible by five

        i.e. lost disit number is 5 divisible

39.     Show that 4832715 is divisible 6 =

        A number is divisible b 6 if it is divisible b both 2

         and 3

                    The lost number is 5 it is not devisible b 2 & 3,

                    hence not divisible by 6

40.   Show that 35256 is divisible 6 =

   A number is divisible by 6 if it is divisible by both 2

   and 3

                The lost number is 6 it is devisible b 2 the sum of the

               disits (3+5+2+5+6)=21

   21     divisible by 3, now givin number is divisible by 6

41. show that 35257 is divisible 8 =

     Thelast 3 disits number is 257 is not divisibele by 8

42 how that 35360 is divisible 8 =

The last 3 disits number is 360 is divisibele by 8

43     is 52563744 divisible by 24   =

the last 3 disit number is 744 which is divisible by 8 and 3 now 24 is divisible

44     what least valuemust be assigned to (*) so that the number 197*5462 is divisible by 9 ?

let the missing disit is x

sum of digits = 1+9+7+*+5+4+6+2 = 34+*= 34+2=36 is divisible 9 now x is 2

PRANJALI PRBHA ( రోజువారి పద్య కథలు ) MALLAPRAGADA

Monday, 3 November 2014

*1.Mallapragada's Mathematics (Numbers-1)

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